find out the special right triangle, find the side BC in the given triangle ? Angle = 45 degree , side = 4 cm

graph each linear equation in two variable. Find at least five solutions in your table of values for each equation. y = 1/3x -1 and y=-5/2x +1

graph each linear equation in two variable. Find at least five solutions in your table of values for each equation. y = 1/3x -1 and  y=-5/2x +1

Answer :- 

In first equation  y  = 1/3x -1 the cofficient of x is 1/3 

so plug the value multiply of 3 so plug x = 0,-3,+3,-6,+6 we get 

x	(x/3) -1
0	-1
-3	-2
3	0
-6	-3
6	1

in second equation  y=-5/2x + 1 the cofficient of x is -5/2 here 2 is in denominator 

so plug the value x multiple of 2 so plug x = 0 ,-2 ,  2,  4, -4 

x	(-5/2)*x +1
0	1
2	-4
-2	6
4	-9
-4	11

now use these values to draw the graph 

graph each linear equation in two variable. Find at least five solutions in your table of values for each equation. y = 1/3x -1 and  y= -5/2x +1

with help of this problem you can easily under stood 

How to solve graph the linear equations ?

how to find the solution table for the equaions ?

how to draw the graph using equations?

explain why the line (x,y,z) = (4,-5,2) + t (2,1,0) is parallel to xy plane

 (x,y,z) = (4,-5,2)  + t (2,1,0)

 here (4,-5,2) is the point and direction is 2i + j + 0k 

as the cofficient of direction of z axis is 0 

so the line is parallel to xy plane 

explain why the line (x,y,z) = (4,-5,2)  + t (2,1,0)  is parallel to xy plane

derivative of sin(sin(sinx))

derivative of sin(sin(sinx)), example of chain rule, how to solve a chain rule problem?, solve the derivative using the chain rule 

derivative of sin(sin(sin x))

use formula of chain rule 

                                      =>d/dx (sin y) = cos y * dy/dx

               the value of y= sin (sin x) 

use above formula we get  
                                    => cos (sin (sinx))*d/dx (sin(sin x))

    now new value of  y = sinx 

use above formula again we get 
                                     => cos (sin (sin x))* cos(sin x) * d/dx sin x 

now use the same formula again we get 
                                     => cos (sin (sin x))* cos(sin x) * cos x 

Answer =  cos (sin (sin x))* cos(sin x) * cos x  

Bromine has two naturally occurring isotopes (and ) and has an atomic mass of 79.904 . The mass of is 80.9163 , and its natural abundance is 49.31%.Calculate the mass of .Br-79 Express your answer using four significant figures. also Calculate the natural abundanc.

Bromine has two naturally occurring isotopes (and ) and has an atomic mass of 79.904 . The mass of first isotopes  is 80.9163 , and its natural abundance is 49.31%.Calculate the mass of .Br-79 Express your answer using four significant figures. also Calculate the natural abundanc.

the atomic mass of first isotopes       (M1)       =80.9163
the atomic mass of second isotopes (M2)        = ?

average atomic mass of  Bromine     (M )        = 79.904

C1 is the abundance % of first isotopes
abundance  % of second isotopes C2 = 100 - C1
                                                         = 100 - 49.31
                                                         = 50.69%  answer

average atomic mass  = (M1*C1+M2*C2)/100

plug the value in this formula we get

Bromine has two naturally occurring isotopes (and ) and has an atomic mass of 79.904 . The mass of is 80.9163 , and its natural abundance is 49.31%.Calculate the mass of .Br-79 Express your answer using four significant figures. also Calculate the natural abundanc.