derivative of sin(sin(sinx)), example of chain rule, how to solve a chain rule problem?, solve the derivative using the chain rule
derivative of sin(sin(sin x))
use formula of chain rule
=>d/dx (sin y) = cos y * dy/dx
the value of y= sin (sin x)
use above formula we get
=> cos (sin (sinx))*d/dx (sin(sin x))
now new value of y = sinx
use above formula again we get
=> cos (sin (sin x))* cos(sin x) * d/dx sin x
now use the same formula again we get
=> cos (sin (sin x))* cos(sin x) * cos x
derivative of sin(sin(sin x))
use formula of chain rule
=>d/dx (sin y) = cos y * dy/dx
the value of y= sin (sin x)
use above formula we get
=> cos (sin (sinx))*d/dx (sin(sin x))
now new value of y = sinx
use above formula again we get
=> cos (sin (sin x))* cos(sin x) * d/dx sin x
now use the same formula again we get
=> cos (sin (sin x))* cos(sin x) * cos x
Answer = cos (sin (sin x))* cos(sin x) * cos x
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