Calculate the amount of carbon dioxide that could be produced when
(i) 1 mole of carbon is burnt in air.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.
(i) 1 mole of carbon is burnt in air.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.
Answer
The balanced reaction of combustion of carbon can be written as:
C + O2 ----------------> CO2
1 1 1
1 1 1
(i) As per the balanced equation, 1 mole of carbon burns in1 mole of dioxygen (air) toproduce1 mole of carbon dioxide.
(ii) According to the question, only 16 g of dioxygen is available. Hence, it will react with 0.5 mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.
(iii) According to the question, only 16 g of dioxygen is available. It is a limitingreactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.
(iii)point is not clear at all ...
ReplyDeleteur in which class?
Delete0.5 ?
ReplyDeleteWhere Is This Come From?
3 point is clear... whether we take 2 moles or 3 moles 16g of o2 will react only with 0.5 moles of carbon. Tgis remain unchanged as only limited oxygen is available
Delete32 g of o2 = 1mole
Delete16g of o2 = 0.5 mole
32 g of o2=44 g of co2
ReplyDelete1 g of o2=44/32 co2
16 g of o2= 44/32x16 =22g co2 in one mole
I didn't understand :/
ReplyDeleteThis is bullshit
ReplyDeleteThis is online confusing site