Thursday, June 7, 2012

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1.

Q -5  Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1.

Answer
0.375 M aqueous solution of sodium acetate  =  1000 mL of solution containing 0.375 moles of sodium acetate
 
∴Number of moles of sodium acetate in 500 mL

                                                                
Molar mass of sodium acetate = 82.0245 g mole–1 (Given)
∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)
                                                                  = 15.38 g
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6 comments:

  1. AbhinavAugust 20, 2013 at 5:22 PM

    Good job. . .

    ReplyDelete
  2. AnonymousMay 20, 2014 at 12:27 PM

    You have helped me a lot :D

    ReplyDelete
  3. AnonymousJuly 4, 2014 at 5:34 AM

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    ReplyDelete
  4. UnknownJuly 31, 2016 at 10:08 AM

    Thank you very much sir :)

    ReplyDelete
  5. UnknownJuly 31, 2016 at 10:08 AM

    Thank you very much sir :)

    ReplyDelete
  6. AnonymousDecember 23, 2017 at 11:29 AM

    If the same princaples are applied then in the question "Calculate the mass of sodium acetate required to prepare 50 mL of a .1 M sodium acetate solution" then the answer would be .4 grams? is that correct?

    ReplyDelete

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