graph each linear equation in two variable. Find at least five solutions in your table of values for each equation. y = 1/3x -1 and y=-5/2x +1
Answer :-
In first equation y = 1/3x -1 the cofficient of x is 1/3
so plug the value multiply of 3 so plug x = 0,-3,+3,-6,+6 we get
x | (x/3) -1 |
0 | -1 |
-3 | -2 |
3 | 0 |
-6 | -3 |
6 | 1 |
in second equation y=-5/2x + 1 the cofficient of x is -5/2 here 2 is in denominator
so plug the value x multiple of 2 so plug x = 0 ,-2 , 2, 4, -4
x | (-5/2)*x +1 |
0 | 1 |
2 | -4 |
-2 | 6 |
4 | -9 |
-4 | 11 |
now use these values to draw the graph
graph each linear equation in two variable. Find at least five solutions in your table of values for each equation. y = 1/3x -1 and y= -5/2x +1 |
with help of this problem you can easily under stood
How to solve graph the linear equations ?
how to find the solution table for the equaions ?
how to draw the graph using equations?
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