Saturday, March 24, 2012

What is the expected freezing point of a 0.80 m solution of CaCl2? (Assume complete dissociation.)


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1 comment:

  1. AnonymousMay 1, 2014 at 12:56 PM

    This answer is incorrect. The formula is Tf=Kf x i x .80. Kf =1.86, and the Van't Hoff factor is 3.
    1.86 x 3 x .80= 4.464. This number will be negative.

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