What is the final pH after 1 drop (0.05 mL) of 6 M HCI is added to 1.0 L of freshly prepared pure water that was originally at a pH of 7.0. Is there a significant pH change?
Answer:-
added volume = 0.05 /1000
= 0.00005 liter
number of add moles = molarity * volume
= 6moles / liter * 0.00005 liter
=0.0003 moles
total volume of solution = 1.0 liter + 0.00005 liter
= 1.00005 liter
molarity of new solution = number of moles / volume in liter
=0.0003/1.00005
= 2.99x10^-4
pH is this new solution= - log [H+]
Reaction is HCl ----------> H+ + Cl -
so [H+] = 2.99x10^-4
hence PH = - log 2.99x10^-4
= 3.52
Hence there are big change in pH value
Answer :- yes there are significant change in pH value
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