solution :-

The titration of 10.00 mL of a diprotic acid solution

we get volume of given diprotic acid (V1) = 10 ml

diprotic acid always gives 2 H + ions

so number of of H + (N1) = 2

molarity of diprotic acid (M1) = ?

21.37 mL of a 0.1432 M NaOH solution

NaOH gives only one OH ions

so value of N2 = 1

Volume V2 = 21.37 ml

and molarity M2 = 0.1432 M

Formula for the reaction

M1*V1* N1= M2*V2*N2

plug all values we get

M1 * 10.00ml*2 = 0.1432 *21.37 ml * 1

solve this condition we get

M1 = 0.1530 M

Answer :- molarity of diprotic acid is 0.1530 M

Q-The titration of 10.00 mL of a diprotic acid solution of unknown concentration requires 21.37 mL of a 0.1432 M NaOH solution. What is the concentration of the diprotic acid solution? |

nice written

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