Q-The titration of 10.00 mL of a diprotic acid solution of unknown concentration requires 21.37 mL of a 0.1432 M NaOH solution. What is the concentration of the diprotic acid solution?

solution :-

The titration of 10.00 mL of a diprotic acid solution

we get volume of given diprotic acid (V1) = 10 ml 

diprotic acid always gives 2 H + ions 

                          so number of of H + (N1) = 2

                   molarity of diprotic acid (M1) = ?

21.37 mL of a 0.1432 M NaOH solution

NaOH gives only one OH ions 

                                           so value of N2 = 1 

                                                 Volume V2 = 21.37 ml

                                        and molarity M2 = 0.1432 M

Formula for the reaction   

                                               M1*V1* N1= M2*V2*N2

          plug all values we get 

                                        M1 * 10.00ml*2 = 0.1432 *21.37 ml * 1 

          solve this condition we get 

                                                             M1 = 0.1530 M 

Answer :-   molarity of diprotic acid is 0.1530 M 

Q-The titration of 10.00 mL of a diprotic acid solution of unknown concentration requires 21.37 mL of a 0.1432 M NaOH solution. What is the concentration of the diprotic acid solution?