Wednesday, June 6, 2012

A glucose solution is prepared by dissolving 5.10 g of glucose, C6H12O6, in 110.5 g of water. What is the molality of the glucose solution? A) 0.283 m B) 0.000256 m C) 0.245 m D) 0.256 m

Question :- A glucose solution is prepared by dissolving 5.10 g of glucose, C6H12O6, in 110.5 g of `water. What is the molality of the glucose solution?
A) 0.283 m B) 0.000256 m C) 0.245 m D) 0.256 m

Answer :- 
 molality = number of moles of solute /mass of solvent in Kg 

The molar mass of glucose is   = 6*C + H*12+ O*6: 
                                                     =180.16 g/mol

So number of moles  of glucose = 5.10 / 180 = 0.0283 mol

These are present in 5.10g + 110.5g of solution = 115.6g
divide by 1000 to convert in Kg 
so 115.6 gram = 0.1156 Kg
 
molality = 0.0283 moles / 0.1156 kg
 
molality = 0.256                                            Answer  = D

Thursday, May 31, 2012

Four of the five answers below are principal characteristics of all chordates. Select the exception. a. post-anal tail b. bony vertebra c. notochord d. dorsal nerve cord e. pharyngeal gill slits


Four of the five answers below are principal characteristics of all chordates. Select the exception.
a.    post-anal tail
b.    bony vertebra
c.    notochord
d.    dorsal nerve cord
e.    pharyngeal gill slits

Ans: b(
  bony vertebra)

Sunday, May 27, 2012

The first known primates were characterized as a. arboreal and nocturnal b. ground-dwelling and nocturnal c. arboreal and diurnal d. ground-dwelling and diurnal e. ground-dwelling and either nocturnal or diurnal


The first known primates were characterized as
a.   arboreal and nocturnal
b.   ground-dwelling and nocturnal
c.   arboreal and diurnal
d.   ground-dwelling and diurnal
e.   ground-dwelling and either nocturnal or diurnal

Ans:  arboreal and nocturnal