Sharks, rays, and skates belong to what group? a. birds b. amphibians c. cartilaginous fish d. bony fish e. reptiles

Sharks, rays, and skates belong to what group?

a. birds

b. amphibians

c. cartilaginous fish

d. bony fish

e. reptiles

Ans: cartilaginous fish

Sharks differ from most other fish in that they lack a. lungs b. scales c. bone d. paired appendages e. fins

Sharks differ from most other fish in that they lack

a. lungs

b. scales

c. bone

d. paired appendages

e. fins

Ans: bone

The term jawless fish could be used to describe a. ostracoderms b. placoderms c. hagfish d. ostracoderms and hagfish e. placoderms and hagfish

The term jawless fish could be used to describe

a. ostracoderms

b. placoderms

c. hagfish

d. ostracoderms and hagfish

e. placoderms and hagfish

Ans: ostracoderms and hagfish

The feeding habits of lampreys are best described as a. suspension feeding b. predatory c. parasitic d. scavenging e. all of the choices Ans:parasitic

The feeding habits of lampreys are best described as

a. suspension feeding

b. predatory

c. parasitic

d. scavenging

e. all of the choices

Ans:

parasitic

step by step balancing of redox reaction KClO3+H2SO4 --KHSO4+HClO4+ClO2+H2O ionic equation :- ClO3^-1 ---------- Clo4^-1 + ClO2

step by step balancing of  redox reaction

KClO3+H2SO4  -->KHSO4+HClO4+ClO2+H2O

ionic equation :-

ClO3^-1  ----------> Clo4^-1 + ClO2

oxidation reaction :- 

oxidation number of Cl in Clo3^-1  is +5 and oxidation  number of Clorine in Clo4^-1 is +7 

here oxidation number of clorine is increasing so its a oxidation reaction 

ClO3^-1  -----> ClO4^-1  

Balance the oxidation reaction by adding the electron 

ClO3^-1  -----> ClO4^-1 + 2e^-1  -------------(1)

(oxidation number of clorine is changing + 5 to + 7 so add 2 electron there to balance the reaction )

reduction reaction :-

oxidation number of Clrine in ClO3^-1 is +5 and in ClO2 oxidation number is +4, oxidation number is decreasing  hence this is 

a reduction reaction 

ClO3^-1 ------> ClO2 

ClO3^-1 + e^-1 -------> ClO2     -------------(2)

(oxidation number of clorine is changing + 5 to + 4 so add 1 electron there to balance the reaction )

multiply by 2 in second equation to make same number of electron in both equation first and second 

2ClO3^-1 + 2e^-1 -------> 2ClO2  -------------(3)

add equation first and third we get 

ClO3^-1 + 2ClO3^-1 + 2e^-1  ----------> Clo4^-1 + 2ClO2  + 2e^-1

calcel out the electron we get 

ClO3^-1 + 2ClO3^-1 ----------> Clo4^-1 + 2ClO2 

H2SO4 is an acid and in acidic redox reaction we always balance the reaction using H+ ions

So balance the charge using H+ ions 

ClO3^-1 + 2ClO3^-1 + 2H+ ----------> Clo4^-1 + 2ClO2 

now Add H2O to balance the complete reaction 

ClO3^-1 + 2ClO3^-1 + 2H+ ----------> Clo4^-1 + 2ClO2 + H2O

Answer :-

               3ClO3^-1 + 2H+ ----------> Clo4^-1 + 2ClO2 + H2O